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標題:
maths ce 2000 mc q12,16,42
發問:
please show me the steps on 2000 ce maths mc q.12,16 and 42 , thanks 更新: not q 42 , is q 39
2000 Q12 Area of triangle BCD = (1/2) (1) (4) = 2 cm^2 Divide the triangle BCD as shown in question Area of the smaller triangle (without shaded area) : Triangle BCD = (3)^2 : (4)^2 = 9:16 So, area of smaller triangle = 9 / (16/2) = 1.125 cm^2 Area of shaded area = 2 - 1.125 = 7/8 (Answer B) 2000 Q16 Option I Becuz 3^3 / 3 = 9 Becuz 3^5 / 3^3 = 9 Option I has common ratio So it is a geometric sequence Option II Becuz 999 / 9 is not equal to 999 / 99 So no common ratio So is not a geometric sequence Option III Becuz -100 / 10 = 1000 / -100 = -10 Option III has common ratio So it is a geometric sequence Answer C 2000 Q 42 Consider x >= y If x>= y Region must be either II, III, or IV Consider 0 <= y <=3, together with x > y Only Possible answer is II or III So answer D 2014-03-03 23:13:32 補充： 2000 Q 42 好難寫 Step 考試見到 E D 題目就 sub 數計 最快
其他解答:
sorry ,not Q42 , is Q39 !
maths ce 2000 mc q12,16,42
發問:
please show me the steps on 2000 ce maths mc q.12,16 and 42 , thanks 更新: not q 42 , is q 39
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最佳解答:2000 Q12 Area of triangle BCD = (1/2) (1) (4) = 2 cm^2 Divide the triangle BCD as shown in question Area of the smaller triangle (without shaded area) : Triangle BCD = (3)^2 : (4)^2 = 9:16 So, area of smaller triangle = 9 / (16/2) = 1.125 cm^2 Area of shaded area = 2 - 1.125 = 7/8 (Answer B) 2000 Q16 Option I Becuz 3^3 / 3 = 9 Becuz 3^5 / 3^3 = 9 Option I has common ratio So it is a geometric sequence Option II Becuz 999 / 9 is not equal to 999 / 99 So no common ratio So is not a geometric sequence Option III Becuz -100 / 10 = 1000 / -100 = -10 Option III has common ratio So it is a geometric sequence Answer C 2000 Q 42 Consider x >= y If x>= y Region must be either II, III, or IV Consider 0 <= y <=3, together with x > y Only Possible answer is II or III So answer D 2014-03-03 23:13:32 補充： 2000 Q 42 好難寫 Step 考試見到 E D 題目就 sub 數計 最快
其他解答:
sorry ,not Q42 , is Q39 !
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