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標題:
負7既負2次方為什麼變分數???
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最佳解答:
首先define咗咩叫0次方先： x^0 =x^1/x^1 =x/x =1 跟住define咩叫負1次方： x^-1 =x^0/x^1 =1/x 再define咩叫負y次方： x^-y =(x^-1)^y =(1/x)^y =1^y/x^y =1/x^y 之後先計(-7)^-2 根據x^-y=1/x^y，x=-7，y=2 (-7)^-2 =1/(-7)^2 =1/(-7)(-7) 負負得正： =1/49 (負數既雙數次方係正數，單數次方係負數)
其他解答:
咁-7有無()先 如果有,就=1/49 如果無=-1/49 *小心()呀!~!|||||(-7)^-2 =[1/(-7)]^2 =(1^2)/(7^2) =1/49|||||-7*-7=49 7*-7=-49 since that that -7 to the power -2 is (-7)^-2, it equals to 1/49 but not 1/-49.
負7既負2次方為什麼變分數???
發問:
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如題, 還有 -7既負2次方=1/-7^2次方 是不是=1/49 如果是,為什麼是正數而不是-1/49???最佳解答:
首先define咗咩叫0次方先： x^0 =x^1/x^1 =x/x =1 跟住define咩叫負1次方： x^-1 =x^0/x^1 =1/x 再define咩叫負y次方： x^-y =(x^-1)^y =(1/x)^y =1^y/x^y =1/x^y 之後先計(-7)^-2 根據x^-y=1/x^y，x=-7，y=2 (-7)^-2 =1/(-7)^2 =1/(-7)(-7) 負負得正： =1/49 (負數既雙數次方係正數，單數次方係負數)
其他解答:
咁-7有無()先 如果有,就=1/49 如果無=-1/49 *小心()呀!~!|||||(-7)^-2 =[1/(-7)]^2 =(1^2)/(7^2) =1/49|||||-7*-7=49 7*-7=-49 since that that -7 to the power -2 is (-7)^-2, it equals to 1/49 but not 1/-49.
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