標題:
我唔識計牙.......教下我啦
發問:
(-r^0/s^-7)^2
最佳解答:
=s^14 2006-10-30 14:26:49 補充: 因為:1. 任何數 (除0之外) 的 0 次方係 = 12. 如果想將分子掉上去分母度, 就要將佢0既指數乘 (-1) 3. (a^n)^m = a^(n x m) = a^nm所以:. -r^0(--------) ^2. .s^-7. . .1=(------) ^2, (because of rule 1). . s^-7= (s^ (-7 x -1))^2, (because of rule 2)= (s^7)^2= s^(7x2), (because of of 3)= s^14
1. (-r^0/s^-7)^2 = (-1/s^-7)^2 = [-1/(1/s^7)]^2 = -(-s^7)^2 = s^14|||||(-r^0/s^-7)^2 =(s^7)^2 =s^14|||||(-r^0/s^-7)^2 = (-1/s^-7)^2 = [-1/(1/s^7)]^2 = -(-s^7)^2 = s^14|||||(-r^0/s^-7)^2 =(-1/s^-7)^2 any number power to 0 =1, e.g r^0=1 =(s^7)^2 =s^14 2006-10-30 14:05:15 補充: insert into layer 3(-s^7)^2|||||我都唔知啊!唔好意思
我唔識計牙.......教下我啦
發問:
(-r^0/s^-7)^2
最佳解答:
=s^14 2006-10-30 14:26:49 補充: 因為:1. 任何數 (除0之外) 的 0 次方係 = 12. 如果想將分子掉上去分母度, 就要將佢0既指數乘 (-1) 3. (a^n)^m = a^(n x m) = a^nm所以:. -r^0(--------) ^2. .s^-7. . .1=(------) ^2, (because of rule 1). . s^-7= (s^ (-7 x -1))^2, (because of rule 2)= (s^7)^2= s^(7x2), (because of of 3)= s^14
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其他解答:1. (-r^0/s^-7)^2 = (-1/s^-7)^2 = [-1/(1/s^7)]^2 = -(-s^7)^2 = s^14|||||(-r^0/s^-7)^2 =(s^7)^2 =s^14|||||(-r^0/s^-7)^2 = (-1/s^-7)^2 = [-1/(1/s^7)]^2 = -(-s^7)^2 = s^14|||||(-r^0/s^-7)^2 =(-1/s^-7)^2 any number power to 0 =1, e.g r^0=1 =(s^7)^2 =s^14 2006-10-30 14:05:15 補充: insert into layer 3(-s^7)^2|||||我都唔知啊!唔好意思
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