標題:
發問:
1. x^2 -7x+12=0 ans. 4,3 2. x^2 +3=5/3 x + 83/36 ans. 5/6 (repeated) 3. 1/2 x^2 +x - 1/3 =0 ans. (-3+√15)/3 , (-3-√15)/3 更新: 林頌賢, it must use quadratic formula to solve it,thx~
最佳解答:
1. x^2 -7x+12=0 ( x - 4 ) ( x - 3 ) = 0 x = 4 or 3 2. x^2 +3=5/3 x + 83/36 36x^2 + 108 = 60x + 83 36x ^ 2 - 60x + 25 ( 6x - 5 )^2 = 0 6x = 5 x = 5 / 6 3. 1/2 x^2 +x - 1/3 =0 3x^2 + 6x - 2 = 0 By Quadratic formula , 圖片參考：http://upload.wikimedia.org/math/3/e/a/3ea647783b5121989cd87ca3bb558916.png x = { -6 + or - √ [ 6 ^ 2 - 4 ( 3 ) ( -2 ) ] } / 2 ( 3 ) x = ( -6 + or - √60 ) / 6 x = √5 / √3 - 1or 1 - √5 / √3
其他解答:
此文章來自奇摩知識+如有不便請留言告知
quadratic formula發問:
1. x^2 -7x+12=0 ans. 4,3 2. x^2 +3=5/3 x + 83/36 ans. 5/6 (repeated) 3. 1/2 x^2 +x - 1/3 =0 ans. (-3+√15)/3 , (-3-√15)/3 更新: 林頌賢, it must use quadratic formula to solve it,thx~
最佳解答:
1. x^2 -7x+12=0 ( x - 4 ) ( x - 3 ) = 0 x = 4 or 3 2. x^2 +3=5/3 x + 83/36 36x^2 + 108 = 60x + 83 36x ^ 2 - 60x + 25 ( 6x - 5 )^2 = 0 6x = 5 x = 5 / 6 3. 1/2 x^2 +x - 1/3 =0 3x^2 + 6x - 2 = 0 By Quadratic formula , 圖片參考：http://upload.wikimedia.org/math/3/e/a/3ea647783b5121989cd87ca3bb558916.png x = { -6 + or - √ [ 6 ^ 2 - 4 ( 3 ) ( -2 ) ] } / 2 ( 3 ) x = ( -6 + or - √60 ) / 6 x = √5 / √3 - 1or 1 - √5 / √3
其他解答:
文章標籤
全站熱搜
留言列表
