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數學高手請進

發問:

寫出以下數列的第五項及第十項 1.{-2n} 2.{n(n+1)} 3.{-3(n-2)} 4.{n(n-1)/n+1} 求以下各數列的通項,並由此求該數列的第十二項 1.0,1,2,3, ... 2.9,18,27,36, ... 3.-2,-4,-6,-8, ... 4.3,5,7,9, ... 5.1/3,1/6,1/9,1/12, ... 6.0.2,0.4,0.6,0.8, ... 請列明步驟 THX!!!

最佳解答:

寫出以下數列的第五項及第十項 1.{-2n} ={-2(5)} =-10 (-2n) ={-2(10)} =-20 2.{n(n+1)} ={(5){(5)+1}} =30 {n(n+1)} ={(10){(10)+1}} =110 3.{-3(n-2)} ={-3((5)-2)} =-9 {-3(n-2)} ={-3((10)-2)} =--24 4.{n(n-1)/n+1} ={(5){(5)-1}/((5)+1} =20/6 =3 1/3 {n(n-1)/n+1} ={(10){(10)-1}/((10)+1} =90/11 =8 2/11 1.0,1,2,3, ... =(n-1) ={(12)-1} =11 2.9,18,27,36, ... =9n =9(12) =108 3.-2,-4,-6,-8, ... =(-2n) ={-2(12)} =-24 4.3,5,7,9, ... =(2n+1) ={2(12)+1} =25 5.1/3,1/6,1/9,1/12, ... =1/3n =1/3(12) =1/36 6.0.2,0.4,0.6,0.8, ... =0.2n =0.2(12) =2.4

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