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How much water would be formed

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How much water would form if 4.8 grams of hydrogen reacted completely with 38.4 grams of oxygen? 點解D人會話係43.2既? 唔該詳細D解釋比我聽

最佳解答:

How much water would form if 4.8 grams of hydrogen reacted completely with 38.4 grams of oxygen? Molar mass of H2 = 1x2 = 2 g/mol Molar mass of O2 = 16x2 = 32 g/mol Molar mass of H2O = 1x2 + 16 = 18 2H-2 + O2 → 2H2O No. of moles of H2 added = 4.8/2 = 2.4 mol No. of moles of O2 added = 38.4/32 = 1.2 mol Mole ratio H2 : O2 = 2 : 1 If all H2 is reacted, O2 needed = 2.4 x (1/2) = 1.2 mol Hence, both H2 and O2 are completely reacted. Mole ratio H2 : H2O = 2 : 2 = 1 : 1 No. of moles of H2 reacted = 2.4 mol No. of moles of H2O formed = 2.4 mol Mass of H2O formed = 2.4 x 18 = 43.2 g Alternative method: Both H2 and O2 are completely reacted. By the law of mass conservation, mass of H2O formed = 4.8 + 38.4 = 43.2 g

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