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發問:
1.一艘潛艇在海面下200m處下降了80m後，再上升100m。求潛艇最後與海面的距離。 2.彼得的年齡是瑪莉的2倍，若他們年齡之和為36，求彼得三年後的年齡。 3.The difference of 2 positive numbers is 120.If 1 number is 4 times the other,findthe 2 numbers.(只想知點列式) i need the steps and the answers. ThZZZZZ 更新: 某長方形的長比闊多4cm。若此長方形的周界為36，求此面積。
最佳解答:
1. 200m + 80m - 100m = 180m 2. let y be mary's age. mary = y peter = 3y mary + peter = 36 y + 3y = 36 4y = 36 y = 8 therefore, mary = 8 years old, and peter = 24 years old thus, peter three year later will be 27 years old ( 24 + 3 ) 3. let one positive number be a, the other be b formula 1 : a - b = 120 a = b + 120 formula 2 : a = 4b therefore, sub. formula 2 to formula 1 4b = b + 120 3b = 120 b = 40 sub. b = 40 to formula 1 a - 40 = 120 a = 160 thus, the number is 40 & 160
1) -200-80 +100= -180 即係海面下180m 2)設彼得是p and 瑪莉是m. p=2m p+m=36 p=24, m=12 彼得=24+3=27 # 3)Let the two numbers be X and Y respectively. X-Y=120 X=4Y 120+Y=4Y so,Y=40,X=160
mathssssss
發問:
1.一艘潛艇在海面下200m處下降了80m後，再上升100m。求潛艇最後與海面的距離。 2.彼得的年齡是瑪莉的2倍，若他們年齡之和為36，求彼得三年後的年齡。 3.The difference of 2 positive numbers is 120.If 1 number is 4 times the other,findthe 2 numbers.(只想知點列式) i need the steps and the answers. ThZZZZZ 更新: 某長方形的長比闊多4cm。若此長方形的周界為36，求此面積。
最佳解答:
1. 200m + 80m - 100m = 180m 2. let y be mary's age. mary = y peter = 3y mary + peter = 36 y + 3y = 36 4y = 36 y = 8 therefore, mary = 8 years old, and peter = 24 years old thus, peter three year later will be 27 years old ( 24 + 3 ) 3. let one positive number be a, the other be b formula 1 : a - b = 120 a = b + 120 formula 2 : a = 4b therefore, sub. formula 2 to formula 1 4b = b + 120 3b = 120 b = 40 sub. b = 40 to formula 1 a - 40 = 120 a = 160 thus, the number is 40 & 160
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其他解答:1) -200-80 +100= -180 即係海面下180m 2)設彼得是p and 瑪莉是m. p=2m p+m=36 p=24, m=12 彼得=24+3=27 # 3)Let the two numbers be X and Y respectively. X-Y=120 X=4Y 120+Y=4Y so,Y=40,X=160
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