標題:
F.4 Maths
發問:
Given that α and α – 2 are the roots of the equation x2 + (3k – 2) x + 48 = 0. (a) Find the values of α(b) If α>0, find the value of k. 更新: why product of roots is α^2 - 2α = - 48
最佳解答:
(a) product of roots= α^2-2α=48 α^2-2α-48=0 (α-8)(α+6)=0 α=8 or -6 (b) sum of roots= 2α-2=-(3k-2) 3k=4-2α k=(4-16)/3 k=-4
The product of roots should be +48.|||||For ax2+bx+c=0, product of roots = c/a.|||||why product of roots is α^2 - 2α = - 48
F.4 Maths
發問:
Given that α and α – 2 are the roots of the equation x2 + (3k – 2) x + 48 = 0. (a) Find the values of α(b) If α>0, find the value of k. 更新: why product of roots is α^2 - 2α = - 48
最佳解答:
(a) product of roots= α^2-2α=48 α^2-2α-48=0 (α-8)(α+6)=0 α=8 or -6 (b) sum of roots= 2α-2=-(3k-2) 3k=4-2α k=(4-16)/3 k=-4
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其他解答:The product of roots should be +48.|||||For ax2+bx+c=0, product of roots = c/a.|||||why product of roots is α^2 - 2α = - 48
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