標題:
MATHS QUESTIONS FORM2
q.1 the time taken by a train to go from station A to stationB is 3 minutes 49 seconds. express this time in(a)minutes, correct to 2 significant figures,(b)seconds , correct to 2 significant figures.q.2 the time required for an anti-virus software to scan all the files of the computer is measured by a... 顯示更多 q.1 the time taken by a train to go from station A to stationB is 3 minutes 49 seconds. express this time in (a)minutes, correct to 2 significant figures, (b)seconds , correct to 2 significant figures. q.2 the time required for an anti-virus software to scan all the files of the computer is measured by a programmer to be 19 minutes 15 seconds, correct to the nearest 5 second. find the percentage error of the measured time correct to 2 significant figures.
最佳解答:
1a. 3 minutes 49 seconds =(3 + 49/60) minutes = 3.81666666666... minutes = 3.8 minutes (corr. to 2 sig. fig.) 1b. 3 minutes 49 seconds = (3x60 + 49) seconds = 229 seconds = 230 seconds (corr. to 2 sig. fig.) 2. 19 minutes 15 seconds = (19 x 60 + 15) seconds = 1155 seconds Maximum absolute error = 5 seconds / 2 = 2.5 seconds So percentage error = 2.5 / 1155 x 100% = 0.216450216 % = 0.22% (corr. to 2 sig. fig.)
其他解答:
MATHS QUESTIONS FORM2
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發問:q.1 the time taken by a train to go from station A to stationB is 3 minutes 49 seconds. express this time in(a)minutes, correct to 2 significant figures,(b)seconds , correct to 2 significant figures.q.2 the time required for an anti-virus software to scan all the files of the computer is measured by a... 顯示更多 q.1 the time taken by a train to go from station A to stationB is 3 minutes 49 seconds. express this time in (a)minutes, correct to 2 significant figures, (b)seconds , correct to 2 significant figures. q.2 the time required for an anti-virus software to scan all the files of the computer is measured by a programmer to be 19 minutes 15 seconds, correct to the nearest 5 second. find the percentage error of the measured time correct to 2 significant figures.
最佳解答:
1a. 3 minutes 49 seconds =(3 + 49/60) minutes = 3.81666666666... minutes = 3.8 minutes (corr. to 2 sig. fig.) 1b. 3 minutes 49 seconds = (3x60 + 49) seconds = 229 seconds = 230 seconds (corr. to 2 sig. fig.) 2. 19 minutes 15 seconds = (19 x 60 + 15) seconds = 1155 seconds Maximum absolute error = 5 seconds / 2 = 2.5 seconds So percentage error = 2.5 / 1155 x 100% = 0.216450216 % = 0.22% (corr. to 2 sig. fig.)
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