標題:
有沒有人慬複數的運算???急!!!
發問:
化簡下列各式，答案以a+bi的形式表示： a)(6+i)x(7-i) b)(2+3i)分之1 c)(2+4i)分之(5+8i) d)(5-3i)分之(7+5i) Answers of the above is ...(As follows) a)43+i b)13分1-(13分3)i c)10分21-(5分1)i d)17分10+(17分23)i
最佳解答:
A. (6+i)*(7-i) = 6(7-i) +i (7-i) =42 -6i +7i -(-1) =43+i B. 1/(2+3i) =(2-3i) / [(2+3i)(2-3i)] = (2-3i) / (4+9) (a+b)(a-b)=a^2 - b^2 = (2/13) - (3/13) i C. (5+8i)/(2+4i) = (5+8i)(2-4i) / (2+4i)(2-4i) = [1/(4+16)] [5(2-4i) +8i(2-4i)] =(1/20) (10 -20i +16i -32(-1)] =(1/20) (42+4i) = (21/10) +(1/5)i D. (7+5i)/ (5-3i) = (7+5i) (5+3i) / (25+9) = (1/34) [35 + 21i + 25i + 15(-1)] =(1/34) (20 +46i) = (10/17) + 23/10) i 2011-05-13 17:21:50 補充： C. 手誤，最後一行改為： =(1/20) (42-4i) = (21/10) -(1/5)i D. 最後一行改為： =(1/34) (20 +46i) = (10/17) + (23/17) i 另外注意你B題的答案是錯的
其他解答:
B 的答案 001對 C ) =(1/20) (10 -20i +16i -32(-1)] =(1/20) (42 - 4i) = (21/10) - (1/5)i D) =(1/34) (20 +46i) = (10/17) + (23/17) i
有沒有人慬複數的運算???急!!!
發問:
化簡下列各式，答案以a+bi的形式表示： a)(6+i)x(7-i) b)(2+3i)分之1 c)(2+4i)分之(5+8i) d)(5-3i)分之(7+5i) Answers of the above is ...(As follows) a)43+i b)13分1-(13分3)i c)10分21-(5分1)i d)17分10+(17分23)i
最佳解答:
A. (6+i)*(7-i) = 6(7-i) +i (7-i) =42 -6i +7i -(-1) =43+i B. 1/(2+3i) =(2-3i) / [(2+3i)(2-3i)] = (2-3i) / (4+9) (a+b)(a-b)=a^2 - b^2 = (2/13) - (3/13) i C. (5+8i)/(2+4i) = (5+8i)(2-4i) / (2+4i)(2-4i) = [1/(4+16)] [5(2-4i) +8i(2-4i)] =(1/20) (10 -20i +16i -32(-1)] =(1/20) (42+4i) = (21/10) +(1/5)i D. (7+5i)/ (5-3i) = (7+5i) (5+3i) / (25+9) = (1/34) [35 + 21i + 25i + 15(-1)] =(1/34) (20 +46i) = (10/17) + 23/10) i 2011-05-13 17:21:50 補充： C. 手誤，最後一行改為： =(1/20) (42-4i) = (21/10) -(1/5)i D. 最後一行改為： =(1/34) (20 +46i) = (10/17) + (23/17) i 另外注意你B題的答案是錯的
其他解答:
B 的答案 001對 C ) =(1/20) (10 -20i +16i -32(-1)] =(1/20) (42 - 4i) = (21/10) - (1/5)i D) =(1/34) (20 +46i) = (10/17) + (23/17) i
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