標題:
physics problem
發問:
A sound wave in air at 20 degree celsius has a frequency of 155 Hz and a displacement amplitude of 4.60×10−3 mm.For this sound wave calculate the pressure amplitude (in Pa).Use 1.42×105 Pa for the adiabatic bulk modulus.Q1: Pmax = ? PaFind the intensity of the wave.Use 1.20... 顯示更多 A sound wave in air at 20 degree celsius has a frequency of 155 Hz and a displacement amplitude of 4.60×10?3 mm. For this sound wave calculate the pressure amplitude (in Pa). Use 1.42×105 Pa for the adiabatic bulk modulus. Q1: Pmax = ? Pa Find the intensity of the wave. Use 1.20 kg/m^3 for the density of air. Q2: I = ? W/m^2 Q3: Find the sound intensity level (in decibels). Use 1.00×10^?12 W/m^2 for the reference intensity. ? dB
Take the speed of sound in air at 20'C be 343 m/s Pressure amplitude = square-root[1.42 x 10^5 x 1.2] x (2.pi x 155) x 4.6x10^-6 Pa = 1.85 Pa (B) Wave inensity = (1/2) x 1.2 x 343 x [(2.pi x 155) x 4.6x10^-6]^2 W/m^2 = 4.13 x 10^-3 W/m^2 (C) Sound intensity level = 10.log(4.13x10^-3/10^-12) dB = 96 dB
其他解答:
physics problem
發問:
A sound wave in air at 20 degree celsius has a frequency of 155 Hz and a displacement amplitude of 4.60×10−3 mm.For this sound wave calculate the pressure amplitude (in Pa).Use 1.42×105 Pa for the adiabatic bulk modulus.Q1: Pmax = ? PaFind the intensity of the wave.Use 1.20... 顯示更多 A sound wave in air at 20 degree celsius has a frequency of 155 Hz and a displacement amplitude of 4.60×10?3 mm. For this sound wave calculate the pressure amplitude (in Pa). Use 1.42×105 Pa for the adiabatic bulk modulus. Q1: Pmax = ? Pa Find the intensity of the wave. Use 1.20 kg/m^3 for the density of air. Q2: I = ? W/m^2 Q3: Find the sound intensity level (in decibels). Use 1.00×10^?12 W/m^2 for the reference intensity. ? dB
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最佳解答:Take the speed of sound in air at 20'C be 343 m/s Pressure amplitude = square-root[1.42 x 10^5 x 1.2] x (2.pi x 155) x 4.6x10^-6 Pa = 1.85 Pa (B) Wave inensity = (1/2) x 1.2 x 343 x [(2.pi x 155) x 4.6x10^-6]^2 W/m^2 = 4.13 x 10^-3 W/m^2 (C) Sound intensity level = 10.log(4.13x10^-3/10^-12) dB = 96 dB
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