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maths~~~~~~
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最佳解答:
By the above result , A1A2/OA1=sqrt3 => A3OA4=60 , A2A3/OA2=sqrt3 => A3OA2=60 A2A1/A1O=sqrt3 => A2OA1=60 OA1=OA2*tan60=(OA3*tan60)*tan60=(OA4*tan60)*tan60*tan60=OA4(tan60)^3 =>OA1=OA4(sqrt3)^4=OA4(3sqrt3) =>OA4=OA1/(3sqrt3)=1/(3sqrt3)=sqrt3/9// 2010-01-23 23:56:01 補充： 打錯 2010-01-23 23:57:36 補充： OA1=OA2*cos60=(OA3*cos60)*tan60=(OA4*cos60)*tan60*cos60=OA4(cos60)^3 =>OA1=OA4(1/2)^3=OA4(1/8) =>OA4=OA1*(8)=8//
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